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AIIMS 2001
Exam
AIIMS
Year
2001
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

AIIMS 2001 · Chemistry · Some Basic Concepts of Chemistry

How many litres of ammonia gas at S.T.P. would be needed to prepare...

How many litres of ammonia gas at S.T.P. would be needed to prepare 100 mL100 \mathrm{~mL} of 2.5M2.5 \mathrm{M} ammonium hydroxide solution?

Options

  1. A5.6 L5.6 \mathrm{~L}
  2. B0.056 L0.056 \mathrm{~L}
  3. C11.2 L11.2 \mathrm{~L}
  4. D0.56 L0.56 \mathrm{~L}

Correct answer

A. 5.6 L5.6 \mathrm{~L}

Step-by-step solution

Molecular weight of NH4OH=35\mathrm{NH}_4 \mathrm{OH}=35 Now, 35 g35 \mathrm{~g} of NH4OH\mathrm{NH}_4 \mathrm{OH} is needed to prepare 1M1 \mathrm{M} solution in 1 litre ⇒35 gNH4OHin1 L\Rightarrow 35 \mathrm{~g} \mathrm{NH}_4 \mathrm{OH} in 1 \mathrm{~L} solution ≡1\equiv 1 molar solution ⇒2.5×35 gNH4OH\Rightarrow 2.5 \times 35 \mathrm{~g} \mathrm{NH}_4 \mathrm{OH} in 1 L1 \mathrm{~L} solution ≡2.5\equiv 2.5 molar solution ⇒2.5×3510 gNH4OH is  100 mL solution ≡2.5 molar solution ⇒8.75 gNH4OH was dissolved. NH3+H2O→NH4OH For  35 gNH4OH,NH3 needed =22.4 L at S.T.P ⇒ for  8.75 gNH4OH,NH3 needed =22.435×8.75 L=5.6 L\begin{aligned} & \Rightarrow \frac{2.5 \times 35}{10} \mathrm{~g} \mathrm{NH}_4 \mathrm{OH} \text{\text{ is } } 100 \mathrm{~mL} \text{ solution } \equiv 2.5 \text{ molar solution } \\ & \Rightarrow \quad 8.75 \mathrm{~g} \mathrm{NH}_4 \mathrm{OH} \text{ was dissolved. } \\ & \mathrm{NH}_3+\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{NH}_4 \mathrm{OH} \\ & \quad \text{\text{ For } } 35 \mathrm{~g} \mathrm{NH}_4 \mathrm{OH}, \mathrm{NH}_3 \text{ needed }=22.4 \mathrm{~L} \text{ at S.T.P } \\ & \Rightarrow \quad \text{\text{ for } } 8.75 \mathrm{~g} \mathrm{NH}_4 \mathrm{OH}, \mathrm{NH}_3 \text{ needed }=\frac{22.4}{35} \times 8.75 \mathrm{~L} \\ &=5.6 \mathrm{~L} \end{aligned}
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