Calculate molarity of 63 % w / w HNO ₃ solution if density is 1.4 ~g / mL .

Step-by-step solution

63 % nitric acid by mass means that mass of nitric acid =63 ~g Mass of solution =100 ~g Molar mass of HNO ₃=63 ~g ~mol ⁻¹ Mole of HNO ₃= 63 ~g 63 ~g ~mol ⁻¹ =1 ~mole Density of solution =1.4 ~g ~mL ⁻¹ Volume of solution = 100 ~g 1.4 ~g ~mL ⁻¹ =71.428 ~mL =0.071428 ~L Molarity of solution = Moles of solute Volume of solution in L = 1.0 0.071428 ~mol ~L ⁻¹=14 M