The distance between the pair of lines (x^2+2 2 x y+2 y^2+4 x+4 2 y+1=0 ), is

Step-by-step solution

Given, equation of pair of lines is (x^2+2 2 x y+2 y^2+4 x+4 2 y+1=0 ) The distance between the pair of lines (a x^2+2 h x y+b y^2+2 g x+2 f y+c=0 ) is given by (d=2 g^2-a c a(a+b) ) Here, (a=1, b=2, c=1, g=2 ) ( ) Required distance (=2 4-1 1(1+2) =2 3 3 =2 )