The product of the perpendicular distances from (1,-1) to the pair of lines x^2-4 x y+y^2=0 , is

Step-by-step solution

The given pair of straight lines, aligned & x^2-4 x y+y^2=0 & x^2-4 x y+4 y^2=3 y^2 & (x-2 y)^2-( 3 y)^2=0 & x-(2+ 3 ) y=0 & or x-(2- 3 ) y=0 & aligned So, perpendicular distances from point (1,-1) to lines (i) d₁= |1+2+ 3 | 1+(2+ 3 )^2 , d₂= |1+2- 3 | 1+(2- 3 )^2 So, aligned d₁ d₂ & = (3+ 3 ) 8+4 3 (3- 3 ) 8-4 3 & = 9-3 64-48 = 6 4 = 3 2 aligned