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NEET
Exam
NEET
Subject
Physics
Chapter
Work, Power and Energy

NEET · Physics · Work, Power and Energy

The relationship between the force F and position x of a body is as...

The relationship between the force FF and position xx of a body is as shown in the figure. The work done in displacing the body from x=1 mx=1 \mathrm{~m} to x=5 mx=5 \mathrm{~m} will be
The relationship between the force F and position x of a body is as shown in the figure. The work done in displacing

Options

  1. A30J30 J
  2. B15 J15 \mathrm{~J}
  3. C25 J25 \mathrm{~J}
  4. D20 J20 \mathrm{~J}

Correct answer

B. 15 J15 \mathrm{~J}

Step-by-step solution

The work done in a F−xF-x graph is calculated by the area under the graph. The given graph can be shown as
The relationship between the force F and position x of a body is as shown in the figure. The work done in displacing
∴\therefore Work done in displacing the object from x=1 mtox=5 mx=1 \mathrm{~m} to x=5 \mathrm{~m} will be W= area under F−x graph = area ABJK+ areaCLDJ + area DGFE+ area GHI=(10×1)+(5×1)+(−5×1)+(12×1×10)=10+5−5+5=15 J\begin{aligned} W &=\text{ area under } F-x \text{ graph } \\ =& \text{ area } A B J K⁺\text{ areaCLDJ } \\ & \quad+\text{ area } D G F E+\text{ area } G H I \\ =&(10 \times 1)+(5 \times 1)+(-5 \times 1)+\left(\frac{1}{2} \times 1 \times 10\right) \\ =& 10+5-5+5=15 \mathrm{~J} \end{aligned}
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