NEETPhysicsWork, Power and Energy
The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 ~m is
Options
- A225 ~J
- B200 ~J
- C400 ~J
- D175 ~J
Correct answer
B. 200 ~J
Step-by-step solution
Word done W= Area ABCEFDA = Area ABCD + Area CEFD = 1 2 (15+10) 10+ 1 2 (10+20) 5=125+75=200 ~J