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NEET
Exam
NEET
Subject
Physics
Chapter
Work, Power and Energy

NEET · Physics · Work, Power and Energy

The work done by a force acting on a body is as shown in the graph....

The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m20 \mathrm{~m} is
The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance

Options

  1. A225 J225 \mathrm{~J}
  2. B200 J200 \mathrm{~J}
  3. C400 J400 \mathrm{~J}
  4. D175 J175 \mathrm{~J}

Correct answer

B. 200 J200 \mathrm{~J}

Step-by-step solution

Word done W=W= Area ABCEFDA = Area ABCD+\mathrm{ABCD}+ Area CEFD
The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance
=12×(15+10)×10+12×(10+20)×5=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5 =125+75=200 J=125+75=200 \mathrm{~J}
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