A body of mass 2.4 ~kg is subjected to a force which varies with distance as shown in figure. The body starts from rest at x=0 . Its velocity at x=9 ~m is

Step-by-step solution

Work done in a moving body is get converted into kinetic energy. aligned & & F d x & = 1 2 m (v^2-0^2 ) & & 1 2 (9+3)(20) & = 1 2 (2.4) v^2 & & V & =10 ~m / s aligned