AP EAMCET201726 Apr 2017Morning ShiftMathematicsPair of LinesActual
If the pair of lines x^2-16 p x y-y^2=0 and x^2-16 q x y-y^2=0 are such that each pair bisects the angle between the other pair, then pq =
Options
- A-1 64
- B1 64
- C-1 8
- D1 8
Correct answer
A. -1 64
Step-by-step solution
We have, equations of pair of straight lines Now, equations of bisectors of these line are -8 p x^2-2 x y+8 p y^2=0 and -8 q x^2-2 x y+8 q y^2=0 According to the given condition in the data, Eqs. (i) and (iv), and Eqs. (ii) and (iii) must be coincident. So, gathered 1 4 q = -16 p 1 = -1 -4 q 1=-64 p q p q= -1 64 gathered