NEETPhysicsWork, Power and Energy
A force (F=k x ) (where, (k ) is a positive constant) is acting on a particle. Work done ( array l|l Column I & Column II (A) In displacement from & (p) Negative x=2 to x=4 & (B) In displacing the body from & (q) Positive x=-4 to x=-2 & (C) In displacing the body from & (r) zero x=-2 to x=+2 & array )
Options
- A(A q, B p, C r )
- B(A p, B p, C r )
- C(A r, B p, C q )
- D(A q, B r, C p )
Correct answer
A. (A q, B p, C r )
Step-by-step solution
From (x=2 ) to (x=4 ), force is positive and displacement is also positive. Hence, the work done is positive. Similar logic can be applied to other parts also.