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NEETPhysicsWork, Power and Energy

A block of mass m = 1 kg, moving on a horizontal surface with speed vi = 2 m s–1 enters a rough patch ranging from x = 0.10 m to x = 2.01 m. The retarding force Fr on the block in this range is inversely proportional to x over this range, F= -k/x for 0.1 2.01 m where k = 0.5 J. What is the final kinetic energy and speed vf of the block as it crosses this patch ?

Options

  1. A0.5J , 1m/s
  2. B0.5J , 2m/s
  3. C1J, 0.5m/s
  4. D2J , 1m/s

Correct answer

A. 0.5J , 1m/s

Step-by-step solution

Correct Option is : (A) 0.5J , 1m/s

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