NEETPhysicsWork, Power and Energy
Two particles A and B are subjected to forces. The ratio of the magnitudes of forces acting on A and B is 1:2 , and the ratio of their speeds is 4:1 . The angle between the force and velocity vectors for particle A is 60^ , while for particle B it is 30^ . The ratio of the instantaneous power delivered to particle A to that of particle B is:
Options
- A2: 3
- B2:1
- C2 3 :1
- D3 :2
Correct answer
A. 2: 3
Step-by-step solution
Instantaneous power is given by P = F v = Fv . For particle A: P_A = F_A v_A 60^ For particle B: P_B = F_B v_B 30^ Taking the ratio of their powers: P_A P_B = ( F_A F_B ) ( v_A v_B ) 60^ 30^ Substituting the given values: P_A P_B = ( 1 2 ) ( 4 1 ) 1/2 3 /2 P_A P_B = 2 1 3 = 2 3 The ratio is 2: 3 . Answer: 2: 3