A particle moves along a straight line such that its position varies with time as x = t^2 + t (where x is in metres and t is in seconds). The instantaneous power delivered to the particle at t = 2 s is 50 W . The force acting on the particle at this instant is:

Step-by-step solution

Given, position of the particle is x = t^2 + t Velocity of the particle is given by: v = dx dt = d dt (t^2 + t) = 2t + 1 At t = 2 s , the instantaneous velocity is: v = 2(2) + 1 = 5 m s ⁻¹ The instantaneous power is given by P = Fv . Substituting the given values: 50 = F 5 F = 10 N Answer: 10 N