An upward force acting on a body varies with its vertical displacement y . The force increases linearly from 0 to 400 N as the displacement increases from y = 0 to y = 10 m. If the total time taken for this displacement is 4 s, the average power delivered by the force is :

Step-by-step solution

Work done by the force is given by the area under the Force-displacement graph. Since the force increases linearly from 0 to 400 N over a displacement of 10 m, the area represents a triangle. W = 1 2 base height W = 1 2 10 400 = 2000 J. Average power is the total work done divided by the total time taken. P_ avg = W t = 2000 4 = 500 W. Answer: 500 W