A car of mass 1000 kg accelerates uniformly from rest to a velocity of 20 m/s in 10 s . The average power delivered by the engine during this time interval is

Step-by-step solution

According to the work-energy theorem, the total work done by the engine equals the change in kinetic energy of the car. Initial kinetic energy, K_i = 0 Final kinetic energy, K_f = 1 2 mv^2 = 1 2 1000 (20)^2 = 200000 J Work done, W = K = 200000 J Average power is the total work done divided by the total time taken: P_ avg = W t = 200000 J 10 s = 20000 W P_ avg = 20 kW Answer: 20 kW