A particle of mass 100 g is thrown vertically upward with a speed of 5 ~m / s . The work done by the force of gravity during the time the particle goes up is

Step-by-step solution

The height (h) transversed by particle while going up is n= u^2 2 g = 25 2 9.8 Work done by gravity force =m g h =0.1 g 25 2 9.8 180^ (angle between force and displacement is 180^ ) W=-0.1 25 2 =-1.25