NEET2012PhysicsWork, Power and EnergyActual
The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is
Options
- A225 J
- B200 J
- C400 J
- D175 J
Correct answer
B. 200 J
Step-by-step solution
Work done W= Area A B C D E F G A= Area A B C D G+ Area D E F G = 1 2 (15+10) 10+ 1 2 (10+20) 5=125+75=200 ~J