A particle of mass 100 g is thrown vertically upwards with a speed of 5 ~m / s . The work done by the force of gravity during the time the particle goes up is

Step-by-step solution

The height ( h )traversed by particle while going up is h= u^2 2 g = 25 2 9.8 Work done by gravity force =m g h =0.1 g 25 2 9.8 180^ [Angle between force and displacement is 180^ ] W=-0.1 25 2 =-1.25 ~J