The work done in pulling up a block of wood weighing 2 kN for a length of 10 m on a smooth plane inclined at an angle of 15^ with the horizontal is

Step-by-step solution

Here : Weight of block w=2 kN , Distance d=10 ~m Angle of inclination on the plane =15^ The block will be pulled up on a smooth plane Hence, force of resistance due to inclination aligned F & =w =2 10^3 15^ & =2 10^3 0.2588 & =0.5176 kN aligned Now work done, aligned W=F d & =0.5176 10^3 10 & =5.17 kJ aligned