AP EAMCET20226 Jul 2022Morning ShiftMathematicsParabolaActual
The centre of the circle that passes through the point (0,1) and touches the curve y=x^2 at (2,4) is
Options
- A( -16 5 , 27 10 )
- B( -16 7 , 53 10 )
- C( -16 5 , 53 10 )
- D( -16 5 , -53 10 )
Correct answer
C. ( -16 5 , 53 10 )
Step-by-step solution
Let equation of circle is x^2+y^2+2 g x+2 f y+c=0 Where centre is (- g ,- f ) Since circle passes through (0,1) 0+1+0+2 f + c =0 c =2 f -1 (2,4) is also on the circle. aligned & 4+16+4 ~g +8 f -2 f -1=0 & 4 ~g +6 f -19=0 aligned Only option (c) satisfy 4 g+6 f-19=0