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AP EAMCET202021 Sep 2020Evening ShiftMathematicsParabolaActual

The equation of the tangent to the parabola (y^2=12 x ) at ((3,-6) ) is

Options

  1. A(x-y+9=0 )
  2. B(x+y+3=0 )
  3. C(x+y-3=0 )
  4. D(x=3 )

Correct answer

B. (x+y+3=0 )

Step-by-step solution

The equation of tangent to the parabola (y^2=12 x ) at ((3,-6) ) is ( array llll y(-6) =6(x+3) x+y+3 =0 array ) Hence, option (b) is correct.

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