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AP EAMCET202018 Sep 2020Morning ShiftMathematicsParabolaActual

The equation of the tangent to the parabola (y^2=16 x ), which is perpendicular to the line (3 x-4 y+5=0 ) is given by

Options

  1. A(4 x-3 y+9=0 )
  2. B(4 x+3 y-9=0 )
  3. C(4 x+3 y+9=0 )
  4. D(4 x-3 y-9=0 )

Correct answer

C. (4 x+3 y+9=0 )

Step-by-step solution

Equation of tangent to the parabola (y^2=16 x ) which is perpendicular to the line (3 x-4 y+5=0 ). So, slope of tangent is ( (- 4 3 ) ) Therefore equation of tangent is ( aligned & y=- 4 3 x+ 4 -4 / 3 y=- 4 3 x-3 4 x+3 y+9 & =0. aligned )

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