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AP EAMCET201822 Apr 2018Morning ShiftMathematicsParabolaActual

The line y=6 x+1 touches the parabola y^2=24 x . The coordinates of a point P on this line, from which the tangent to y^2=24 x is perpendicular to the line y=6 x+1 , is

Options

  1. A(-1,-5)
  2. B(-2,-11)
  3. C(-6,-35)
  4. D(-7,-41)

Correct answer

C. (-6,-35)

Step-by-step solution

Given, equation of line is y = 6x + 1 and equation of pa rab ola is y^2=24 x . The locus of the point of intersection of perpendicular tangent to a parabola is its directrix. So, required point is the point of intersection of y = 6x + 1 and direc trix x = − 6. Hence, its coordinates are (− 6, − 35).

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