There are 6 different novels and 3 different poetry books on a table. If 4 novels and 1 poetry book are to be selected and arranged in a row on a shelf such that the poetry book is always in the middle, then the number of such possible arrangements is

Step-by-step solution

Number of ways 4 novels can be selected out of 6 novels - ^6 C₄ and number of ways 1 poctry book can be selected out of 3= ^3 C₁ Number of arrangements can be made with 4 novels and 1 poetry book keeping poetry book in the middle =4 ! Total required arrangements = ^6 C₄ ^3 C₁ 4!=1080 .