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AP EAMCET202420 May 2024Evening ShiftMathematicsPermutation and CombinationActual

A test containing 3 objective type of questions is conducted in a class. Each question has 4 options and only one option is the correct answer. No two students of the class have answered identically and no student has written all correct answers. If every student has attempted all the questions, then the maximum possible number of students who has written the test is

Options

  1. A80
  2. B63
  3. C15
  4. D11

Correct answer

B. 63

Step-by-step solution

Total number of possible answer =4 4 4=64 Total answer given =64-1=63 Maximum possible number of students =63

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