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AP EAMCET202420 May 2024Evening ShiftMathematicsPermutation and CombinationActual

The number of numbers lying between 1000 and 10000 such that every number contains the digits 3 and 7 only once without repetition is

Options

  1. A1140
  2. B918
  3. C720
  4. D810

Correct answer

C. 720

Step-by-step solution

No. of ways 0 = ^3 C ₂ 2 8=48 Total no. of ways aligned & = ^4 C₂ 2 8 8=64 12=768 & Required number =768-48=720 aligned

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