AP EAMCET202318 May 2023Evening ShiftMathematicsPermutation and CombinationActual
A question paper has two sections A and B in which section-A had 8 questions and section- B has 6 questions. A student has to answer a total of 10 questions, choosing atleast 4 questions from section- A and atleast 3 questions from section-B. Then the number of ways a student can answer that paper is
Options
- A800
- B820
- C840
- D986
Correct answer
D. 986
Step-by-step solution
The student may select: (i) (4 out of 8 from A) and (6 out of 6 from B) (ii) (5 out of 8 from A) and (5 out of 6 from B) (iii) (6 out of 8 from A) and (4 out of 6 from B) (iv) (7 out of 8 from A) and ( 3 out of 6 from B) The no, of ways of these selections are:- (i) ^8 C ₄ ^6 C ₆=70 1=70 (ii) ^8 C ₅ ^6 C ₅=56 6=336 (iii) ^8 C ₆ ^6 C ₄=28 15=420 (iv) ^8 C ₇ ^6 C ₃=8 20=160 The required no. of ways =70+336+420+160=986 .