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AP EAMCET202124 Aug 2021Morning ShiftMathematicsPermutation and CombinationActual

Statement I The number of ways of distributing 10 identical balls in 4 distinct boxes such that no box is empty is ^9 C₃ . Statement II The number of ways of choosing 3 places from 9 different places is ^9 C ₃ .

Options

  1. AStatement I is true, statement II is true, statement II is not a correct explanation for statement I
  2. BStatement I is true, statement II is false
  3. CStatement I is false, statement II is true
  4. DStatement I is true, statement II is true, statement II is a correct explanation for statement I

Correct answer

A. Statement I is true, statement II is true, statement II is not a correct explanation for statement I

Step-by-step solution

Statement I The number of ways of distributing 10 identical balls in 4 distinct boxes such that no box is empty is ^9 C₃ . n identical things can be distributed to different boxes by t-1 r-1 ways such that no box is empty. 10 identical balls can be distributed to 4 distinct boxes by 10-1 4-1 ways i.e. ^9 C₃ ways Statement II The number of ways of choosing 3 places from 9 different places is ^9 C₃ (true) Statement I is true statement II is true, statement II is not a correct explanation for statement I.

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