AP EAMCET202123 Aug 2021Evening ShiftMathematicsPermutation and CombinationActual
The number of distinct positive integers can be formed using 0,1,2,3 where each integer used at most once is equal to
Options
- A84
- B64
- C48
- D36
Correct answer
C. 48
Step-by-step solution
Given integers, 0, 1, 2, 3 Case I The number of ways to form four digit integers =3 3 2 1=18 (first place can be filled by one of the three choices 1,2,3) Case II The number of 3-digit integers =3 3 2=18 Case III The number of 2-digit integers =3 3=9 Case IV The number of 1 -digit integer =3 The number of distinct positive integers =18+18+9+3=48