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AP EAMCET202123 Aug 2021Evening ShiftMathematicsPermutation and CombinationActual

The number of distinct positive integers can be formed using 0,1,2,3 where each integer used at most once is equal to

Options

  1. A84
  2. B64
  3. C48
  4. D36

Correct answer

C. 48

Step-by-step solution

Given integers, 0, 1, 2, 3 Case I The number of ways to form four digit integers =3 3 2 1=18 (first place can be filled by one of the three choices 1,2,3) Case II The number of 3-digit integers =3 3 2=18 Case III The number of 2-digit integers =3 3=9 Case IV The number of 1 -digit integer =3 The number of distinct positive integers =18+18+9+3=48

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