The number of ways in which 3 boys and 2 girls can sit on a bench so that no two boys are adjacent is ______

Step-by-step solution

As no two boys can sit together their arrangement will be B   G   B   G   B Boys will be arranged first and then girls will sit in between them. The number of ways of arranging boys will be 3 ! = 3 × 2 × 1 = 6 And, number of ways of arranging girls will be 2 ! = 2 × 1 = 2 Therefore, total number of ways they can be arranged will be = 6 × 2 = 12