The number of ways of choosing a committee from four men and six women so that the committee includes at least two men and exactly twice as many women as men is

Step-by-step solution

4 men, 6 women All possible cases for committee are ( 2 men, 4 women ) , ( 3 men, 6 women ) Total ways = 4 C 2 · 6 C 4 + 4 C 3 · 6 C 6 = 6 × 15 + 4 × 1 = 94