A person invites 8 guests to a dinner and places 5 of them at one table and the remaining 3 at another, both the tables being round. The number of ways in which the guests can be arranged is

Step-by-step solution

The number of ways to select 5 person out of 8 is ^8 C₅ . Now, number of ways to place 5 on round table is 4 ! and number of ways to place 3 on round table is 2 !. So, required number of ways = ^8 C₅ 4 ! 2 ! = 8 7 6 3 2 4 3 2 2=42 64=2688 Hence, option (b) is correct.