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AP EAMCET201824 Apr 2018Morning ShiftMathematicsPermutation and CombinationActual

There are three sections in a question paper, each containing 4 questions. If a candidate has to answer only 5 questions from this paper without leaving any section, then number of ways the candidate can make the choice of questions is

Options

  1. A624
  2. B704
  3. C384
  4. D432

Correct answer

A. 624

Step-by-step solution

Number of ways to select 5 questions from these sections as follows, A B C Section array lll 2 & 2 & 1 2 & 1 & 2 1 & 2 & 2 array gathered array lll 3 & 1 & 1 1 & 3 & 1 1 & 1 & 3 array . ^4 C₂ ^4 C₂ ^4 C₁ 3+ ^4 C₃ ^4 C₁ ^4 C₁ 3 4 ! 2 ! 2 ! 4 ! 2 ! 2 ! 4 ! 1 ! 3 ! 3+ 4 ! 3 ! 1 ! 4 ! 1 ! 3 ! 4 ! 1 ! 3 ! 3 432+192=624 gathered

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