AP EAMCET2013MathematicsPermutation and Combination
10 men and 6 women are to be seated in a row so that no two women sit together. The number of ways they can be seated, is
Options
- A11 ! 10 !
- B11 ! 6 ! 5 !
- C10 ! 9 ! 5 !
- D11 ! 10 ! 5 !
Correct answer
D. 11 ! 10 ! 5 !
Step-by-step solution
W W W W W W W W W First, we arrange 10 men in a row at alternate position. So, number of ways formula =10 ! Now, 6 women can arrange in 11 positions So, number of ways for women = ¹¹ P₆ Required number of aligned S & =10 ! ¹¹ P₆ & = 10 ! 11 ! 5 ! aligned