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AP EAMCET2013MathematicsPermutation and Combination

10 men and 6 women are to be seated in a row so that no two women sit together. The number of ways they can be seated, is

Options

  1. A11 ! 10 !
  2. B11 ! 6 ! 5 !
  3. C10 ! 9 ! 5 !
  4. D11 ! 10 ! 5 !

Correct answer

D. 11 ! 10 ! 5 !

Step-by-step solution

W W W W W W W W W First, we arrange 10 men in a row at alternate position. So, number of ways formula =10 ! Now, 6 women can arrange in 11 positions So, number of ways for women = ¹¹ P₆ Required number of aligned S & =10 ! ¹¹ P₆ & = 10 ! 11 ! 5 ! aligned

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