A bag contains 4 red and 5 black balls. Another bag contains 3 red and 6 black balls. If one ball is drawn from first bag and two balls from the second bag at random, the probability that out of the three, two are black and one is red, is

Step-by-step solution

Balls in Bag I are 4 Red and 5 black P( Red balls in bag I)= 4 9 P ( Black balls in bag I )= 5 9 Balls in Bag II are 3 red and 6 black P ( Red balls in bag II )= 3 9 P ( Black balls in bag II )= 6 9 Required probability (2 black and 1 red) = 4 9 6 9 5 8 +2 ( 5 9 3 9 6 8 )= 25 54