AP EAMCET202422 May 2024Morning ShiftMathematicsProbabilityActual
8 teachers and 4 students are sitting around a circular table at random, then the probability that no two students sit together is:
Options
- A7 88
- B14 33
- C8 33
- D7 33
Correct answer
D. 7 33
Step-by-step solution
Total number of arrangements of 8 teachers and 4 students in circular table =(8+4-1)!=11 ! Number of arrangements of 8 teachers and 4 students in circular table such that no two students sit together = ^8 C₄ 4!(8-1)!= ^8 C₄ 4! 7! Required probability = ^8 C₄ 4! 7! 11! = 8 7 6 5 4! 4! 7! 11 10 9 8 7! = 7 33 .