When an unfair dice is thrown, the probability of getting a number k on it is P ( X =k)=k^2 P , where k=1,2,3,4,5,6 and X is the random variable denoting a number on the dice, then the mean of X is

Step-by-step solution

aligned & P(X=k)=k^2 P, _ i=1 ^6 P(X=i)=1 & P(X=1)+P(X=2)+ .+P(X=6)=1 & P+4 P+9 P+16 P+25 P+36 P=1 P= 1 91 & Mean =1 1 91 +2 4 91 +3 9 91 +4 16 91 +5 25 91 +6 36 91 & = 441 91 . aligned