The sample containing same no. of ' Na ' atom as there are ' Na ' atoms in 5.3 g of ( Na ₂ CO ₃ ) is - (A) 4 g of NaOH (B) 5.85 g of NaCl (C) 0.25 mol of ( Na ₂ SO ₄ ) (D) 5.6 g of ( Na ₃ PO ₄ )

Step-by-step solution

Calculate moles of Na in 5.3 g of ( Na ₂ CO ₃ ) Molar mass of ( Na ₂ CO ₃ ) : - ( Na =23, ~g / mol (2 Na =46 ~g ) ) - ( C =12, ~g / mol ) - ( O =16, ~g / mol (3 O =48 ~g ) ) Total: (46+12+48=106 ~g / mol ) Moles of ( Na ₂ CO ₃ ) in 5.3 g : Moles (= 5.3 ~g 106 ~g / mol 0.050 ~mol ) Number of Na atoms in ( Na ₂ CO ₃ ) : (0.050 ~mol 2=0.100 ~mol ) of Na Determine equivalent samples (A) 4 g of INaOII: - Molar mass of ( NaOHI =23+16+1=40, ~g / mol ) Moles of ( Na = 4 ~g 40 ~g / mol =0.1 ~mol ) (B) 5.85 g of NaCl : - Mol