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NEETChemistrySome Basic Concepts of Chemistry

Match the following. ( array ll|l A. & 88 g of CO ₂ & 1. 0.2 ~mol B. & 6.022 ~mol molecules of H ₂ O & 2. 2 ~mol C. & 5.6 ~L of O ₂ at STP & 3. 1 ~mol D. & 96 g of ₂ O ₂ & 4. 6.022 ~mol molecules D. & 1 mole of any gas & 5. 3 ~mol array )

Options

  1. A((A) (2),(B) (3),(C) (1),(D) (5), E) (4) )
  2. B((A) (1),(B) (2),(C) (5),(D) (3),(E) (4) )
  3. C((A) (5),(B) (4),(C) (3),(D) (2),(E) (1) )
  4. D((A) (2),(B) (3),(C) (1),(D) (5),(E) (4) )

Correct answer

A. ((A) (2),(B) (3),(C) (1),(D) (5), E) (4) )

Step-by-step solution

A. Number of moles of ( CO ₂ ) molecule (= Weight in gram of CO ₂ Molecular weight of CO ₂ = 88 44 =2 ~mol ) B. 1 mole of a substance (=N_A ) molecules (=6.022 10²³ ) molecules (= ) Avogadro number (=6.022 10²³ ) molecules of ( H ₂ O =1 ~mol ) C. (22.4 Lof O ₂ ) at STP (=1 ~mol ) (5.6 LofO ₂ ) at STP (= 5.6 22.4 ~mol =0.25 ~mol ) D. Number of moles of (96 ~g of O ₂= 96 32 ~mol =3 ~mol ) E. 1 mole of any gas (= ) Avogadro number (=6.022 10²³ ) molecules

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