NEET
- Exam
- NEET
- Subject
- Chemistry
- Chapter
- Some Basic Concepts of Chemistry
NEET · Chemistry · Some Basic Concepts of Chemistry
Match the following. ( A. 88 g of CO _2 1. 0.2 mol B. 6.022 mol...
Match the following.
(
)
| A. | 88 g of CO _2 | 1. 0.2 mol |
| B. | 6.022 mol molecules of H_2 O | 2. 2 mol |
| C. | 5.6 L of O_2 at STP | 3. 1 mol |
| D. | 96 g of _2 O_2 | 4. 6.022 mol molecules |
| D. | 1 mole of any gas | 5. 3 mol |
Options
- A((A) \rightarrow(2),(B) \rightarrow(3),(C) \rightarrow(1),(D) \rightarrow(5), E) \rightarrow(4))
- B((A) \rightarrow(1),(B) \rightarrow(2),(C) \rightarrow(5),(D) \rightarrow(3),(E) \rightarrow(4))
- C((A) \rightarrow(5),(B) \rightarrow(4),(C) \rightarrow(3),(D) \rightarrow(2),(E) \rightarrow(1))
- D((A) \rightarrow(2),(B) \rightarrow(3),(C) \rightarrow(1),(D) \rightarrow(5),(E) \rightarrow(4))
Correct answer
A. ((A) \rightarrow(2),(B) \rightarrow(3),(C) \rightarrow(1),(D) \rightarrow(5), E) \rightarrow(4))
Step-by-step solution
A. Number of moles of (\mathrm{CO}_2) molecule (=\frac{\text{ Weight in gram of } \mathrm{CO}_2}{\text{ Molecular weight of } \mathrm{CO}_2}=\frac{88}{44}=2 \mathrm{ mol})
B. 1 mole of a substance molecules (=6.022 \times 10^{23}) molecules
Avogadro number
(=6.022 \times 10^{23}) molecules of (\mathrm{H}_2 \mathrm{O}=1 \mathrm{ mol})
C. (22.4 \mathrm{Lof} \mathrm{O}_2) at STP (=1 \mathrm{ mol})
(5.6 \mathrm{LofO}_2) at STP (=\frac{5.6}{22.4} \mathrm{ mol}=0.25 \mathrm{ mol})
D. Number of moles of (96 \mathrm{ g} \mathrm{of} \mathrm{O}_2=\frac{96}{32} \mathrm{ mol}=3 \mathrm{ mol})
E. 1 mole of any gas Avogadro number (=6.022 \times 10^{23}) molecules