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NEETChemistrySome Basic Concepts of Chemistry

The number of carbon atoms present in 18 g of glucose is : (Given : N_A = 6.022 10²³ particles mol ⁻¹ )

Options

  1. A6.022 10²²
  2. B3.613 10²³
  3. C7.226 10²³
  4. D3.613 10²²

Correct answer

B. 3.613 10²³

Step-by-step solution

The chemical formula of glucose is C₆H₁₂O₆ . Molar mass of glucose = (6 12) + (12 1) + (6 16) = 180 g mol ⁻¹ . Number of moles of glucose = 18 180 = 0.1 mol. One molecule of glucose contains 6 carbon atoms. Number of moles of carbon atoms = 6 0.1 = 0.6 mol. Total number of carbon atoms = 0.6 N_A = 0.6 6.022 10²³ = 3.6132 10²³ 3.613 10²³ . Answer: 3.613 10²³

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