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NEETChemistrySome Basic Concepts of Chemistry

Match List-I with List-II for nitrogen gas ( N ₂ ) and select the correct option. List-I List-II (A) Mass of 1 atom of nitrogen (in g) (I) 11.2 (B) Number of molecules in 14 g of N ₂ (II) 14 N_A (C) Volume of 14 g of N ₂ at STP (in L) (III) N_A (D) Number of atoms in 14 g of N ₂ (IV) 0.5 N_A ( N_A is Avogadro's number)

Options

  1. A(A)-(II), (B)-(III), (C)-(I), (D)-(IV)
  2. B(A)-(IV), (B)-(II), (C)-(I), (D)-(III)
  3. C(A)-(II), (B)-(IV), (C)-(III), (D)-(I)
  4. D(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Correct answer

D. (A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Step-by-step solution

(A) Mass of 1 mole of N atoms is 14 g . Therefore, the mass of 1 atom of nitrogen is 14 N_A g . (B) Molar mass of N ₂ = 28 g mol ⁻¹ . Number of moles in 14 g of N ₂ = 14 28 = 0.5 mol . The number of molecules is 0.5 N_A . (C) Volume of 1 mole of an ideal gas at STP is 22.4 L . Volume of 0.5 mol of N ₂ = 0.5 22.4 = 11.2 L . (D) Each N ₂ molecule contains 2 atoms. Total number of atoms = 2 0.5 N_A = N_A . Therefore, the correct matching is (A)-(II), (B)-(IV), (C)-(I), (D)-(III). Answer: (A)-(II), (B)-(IV), (C)-(I), (

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