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NEET2010ChemistrySome Basic Concepts of ChemistryActual

Stomach acid, a dilute solution of HCl in water, can be neutralized by reaction with sodium hydrogen carbonate, NaHCO _ 3(a q) + HCl _ (a q) NaCl _ (a q) + H ₂ O _ (l) + CO _ 2(g) How many milliliters of 0.125 M NaHCO ₃ solution are needed to neutralize 18.0 ~mL of 0.100 M HCl ?

Options

  1. A14.4 ~mL
  2. B12.0 ~mL
  3. C14.0 ~mL
  4. D13.2 ~mL

Correct answer

A. 14.4 ~mL

Step-by-step solution

aligned & Given, M_ HCl =0.1 M , V_ HCl =18.0 ~mL & M_ NaHCO ₃ =0.125 M , V_ NaHCO ₃ = ? aligned On applying, M_ HC V_ HCl =M_ NaHCO ₃ V_ NaHCO ₃ 0.1 18=0.125 V_ NaHCO ₃ M_ NaHCO ₃ =14.4 ~mL Thus, 14.4 ~mL of the 1.25 M NaHCO M ₃ solution is needed to neutralise 18.0 ~mL of the 0.100 M HCl solution.

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