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NEET2009ChemistrySome Basic Concepts of ChemistryActual

To a 25 ~mL H ₂ O ₂ solution, excess of acidified solution of KI was added. The iodine liberated required 20 ~mL of 0.3 ~N Na ₂ ~S ₂ O ₃ solution. The volume strength of H ₂ O ₂ solution is

Options

  1. A1.344 ~g / L
  2. B3.244 ~g / L
  3. C5.4 ~g / L
  4. D4.08 ~g / L

Correct answer

D. 4.08 ~g / L

Step-by-step solution

aligned & 2 KI + H ₂ SO ₄+ H ₂ O ₂ K ₂ SO ₄+2 H ₂ O + I ₂ & 2 Na ₂ ~S ₂ O ₃+ I ₂ Na ₂ ~S ₄ O ₆+2 NaI aligned milli eq. of H ₂ O ₂ in 25 ~mL =20 0.3=6 milli eq. of H ₂ O ₂ in 1000 ~mL = 6 25 1000=240 Equivalent per litre = 240 1000 Gram per litre of H ₂ O ₂= 240 1000 17=4.08 ~g / L (Equivalent weight of H ₂ O ₂= 34 2 =17 ).

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