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NEET2017ChemistrySome Basic Concepts of ChemistryActual

Combustion of glucose takes place according to the equation, C ₆ H ₁₂ O ₆+6 O ₂ 6 CO ₂+6 H ₂ O H=-72 k - cal The energy required for combustion of 1.6 g of glucose is

Options

  1. A0.064 k-cal
  2. B0.64 k-cal
  3. C6.4 k - cal
  4. D64 k-cal

Correct answer

B. 0.64 k-cal

Step-by-step solution

gathered Molar mass of C ₆ H ₁₂ O ₆=180 ~g ~mol ⁻¹ 180 ~g of glucose require energy =72 kcal 1.6 ~g of glucose require energy = 72 1.6 180 gathered =0.64 k cal

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