NEET2016ChemistrySome Basic Concepts of ChemistryActual
Solid NaHCO ₃ will be neutralised by 40.0 mL of 0.1 M H ₂ SO ₄ solution. What would be the weight of solid NaHCO ₃ in gram?
Options
- A0.672 g
- B6.07 g
- C17 g
- D20 g
Correct answer
A. 0.672 g
Step-by-step solution
The required neutralisation reaction is, 2 NaHCO ₃+ H ₂ SO ₄ Na ₂ SO ₄+2 H ₂ O +2 CO ₂ m -moles of H ₂ SO ₄=M V_ mL =40.0 0.1=4 ~m -mole or m-moles of NaHCO ₃ neutralised =4 2=8 ~m -mole But, m-mole = w m 1000 aligned 8 & = w 84 1000 w & = 84 8 1000 w=0.672 ~g aligned