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AP EAMCET202419 May 2024Evening ShiftMathematicsProbabilityActual

If 7 different balls are distributed among 4 different boxes, then the probability that the first box contains 3 balls is

Options

  1. A35 128 ( 3 4 )^3
  2. B35 64 ( 3 4 )^4
  3. C7 8 ( 3 4 )^7
  4. D5 16 ( 3 4 )^5

Correct answer

B. 35 64 ( 3 4 )^4

Step-by-step solution

Since, total number of ways of distributing of 7 balls in 4 box =4^7 Total number of ways such that first box contain 3 balls = ^7 C₃ 3^4 So, required probability = ^7 C₃ 3^4 4^7 = 35 64 ( 3 4 )^4 .

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