In a consignment of 15 articles, it is found that 3 are defective. If a sample of 5 articles is chosen at random from it, then the probability of having 2 defective articles is

Step-by-step solution

Define the variables - Total articles =15 - Defective articles =3 - Non-defective articles =15-3=12 - Sample size =5 - We need the probability of choosing exactly 2 defective articles in this sample. Use combinations to calculate possible outcomes The probability can be calculated using combinations, as we are dealing with a selection of items without regard to the order. 1. Number of ways to choose 2 defective articles out of 3: 3 2 = 3! 2!(3-2)! =3 2. Number of ways to choose 3 nondefective articles out of 12: 12