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AP EAMCET202418 May 2024Morning ShiftMathematicsProbabilityActual

A box contains 20% defective bulbs. Five bulbs are chosen randomly from this box. The probability that exactly 3 of the chosen bulbs are defective is

Options

  1. A32 625
  2. B32 125
  3. C16 625
  4. D16 125

Correct answer

A. 32 625

Step-by-step solution

Given, P( defective bulbs )=20 %= 1 5 Let, p= 1 5 q= 4 5 Now, P (exactly 3 defective bulbs) = ^5 C ₃= ( 1 5 )^3 ( 4 5 )^2= 5 4 2 1 125 16 25 = 32 625

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