AP EAMCET202418 May 2024Morning ShiftMathematicsProbabilityActual
If a random variable X satisfies poisson distribution with a mean value of 5 , then probability that X 3 is
Options
- A37 2 e^5
- B6 e^5
- C6 e⁻⁵
- D37 2 e⁻⁵
Correct answer
D. 37 2 e⁻⁵
Step-by-step solution
Given x satisfies poisson with mean value is 5 So, P (x 3)= P (x=0)+ P (x=1)+ P (x=2)=e⁻⁵ 5^0 0! +e⁻⁵ 5^1 1! +e⁻⁵ 5^2 2! =e⁻⁵ (1+5+ 25 2 )= 37 2 e⁻⁵