If four dice are thrown simultaneously, then the probability that none of the dice shows the number 1 on its face, is

Step-by-step solution

Since there are 6 total samples. Hence the probability of getting number 1 on face = 1 6 Probability of not getting number 1 on face of a dice =1- 1 6 = 5 6 Since 4 dice are thrown simultaneously. Hence probability of not getting number 1 on face of any of the dice = ( 5 6 ) ( 5 6 ) ( 5 6 ) ( 5 6 )= 625 1296