AP EAMCET202315 May 2023Morning ShiftMathematicsProbabilityActual
The range of a random variable X is 0,1,2 . If P(X=0)=3 C ^3, P ( X =1)=4 C -10 C ^2 and P ( X =2)=5 C -1 , then the value of C is
Options
- A2 3
- B1 3
- C. 5 3
- D4 3
Correct answer
B. 1 3
Step-by-step solution
aligned & P(X=0)+P(X=1)+P(X=2)=1 & 3 c^3+4 c-10 c^2+5 c-1=1 & 3 c^3+4 c-10 c^2+5 c-2=0 & (c-1)(3 c-1)(c-2)=0 & c= 1 3 , 1,2 . aligned When c=2 , Then P(X=2)=10-1=9>1 c 2 When c=1 , Then P(X=2)=5-1=4>1 c 1 So, c= 1 3 .